Pow

Arguments

Description

This function increases 'Expression1' (basis) to the power of 'Expression2' (exponent): ('Expression1')'Expression2'

Example

Calculating some important powers

Solution

(2)0 = Pow(2, 0) = 1

(2)-2 = Pow(2, -2) = 0.25

(-2)2 = Pow(-2, 2) = 4

(10)lg 2 = Pow(10, lg 2) = 2

(0)-1 = Pow(0, -1) = +∞ (infinity)

Tip
	The exponentiation of 0 with -1, which is equivalent to a division by 0, does not return an error message but the limit value +infinity.